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What is the derivative of SIN 3x?
Thanks soo much!
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Wit the derivative of sin3x we need to do the chain rule. The derivative of sin is cosine. So using the chain rule, the derivative of sin3x equals cos3x * 3 or 3cos3x.
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find the relative extrema.
f (x) = cube radical sign (x-1)
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jgaines001 wrote:
find the relative extrema.
f (x) = cube radical sign (x-1)
All you do is take the derivative of that function, set it equal to zero and solve for x. Then check if you take the value of the derivative to the left and right of that given x value, does the derivative go from negative to positive or from positive to negative. If it does, then you have a relative extrema there.
Mr. Math
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The chain rule states that when:
y = f(B)
and,
B = g(x)
dy/dx = dy/dB * dB/dx
So in this case, take y = sin(B), and B = 3x:
dy/dB = cos(B)
dB/dx = 3
Therefore:
dy/dx = 3*cos(B)
Substituting what B is:
dy/dx = 3cos(3x)
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